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Home/ Questions/Q 4321412
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T08:44:35+00:00 2026-05-21T08:44:35+00:00

i have following HTML code:- <table class=results> <tr> <td> <a href=..>link</a><span>2nd Mar 2011</span><br>XYZ Consultancy

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i have following HTML code:-

<table class="results">
  <tr>
    <td>
      <a href="..">link</a><span>2nd Mar 2011</span><br>XYZ Consultancy Ltd<br>
       <div>....</div>
    </td>
  </tr>
</table>

I am using lxml+python code to parse above HTML file. I want to retrieve “XYZ Consultancy Ltd” but I am not able to find out how to do this. So far my code is as follows:-

import lxml.html
for el in root.cssselect("table.results"):    
 for el2 in el: #tr tags
  for e13 in el2:#td tags
     for e14 in e13:
      if ( e14.tag == 'a') :
         print "keyword: ",e14.text_content()
      if (e14.tag == 'span'):
         print "date: ",e14.text_content()
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T08:44:35+00:00Added an answer on May 21, 2026 at 8:44 am

    You can use the CSS Selector +, a direct adjacent combinator, to get at the <br> preceding the text. Then, the target text is contained in its tail attribute.

    import lxml.html
    root = lxml.html.fromstring('''
    <table class="results">
      <tr>
        <td>
          <a href="..">link</a><span>2nd Mar 2011</span><br>XYZ Consultancy Ltd<br>
           <div>....</div>
        </td>
      </tr>
    </table>
    ''')
    for br_with_tail in root.cssselect('table.results > tr > td > a + span + br'):
        print br_with_tail.tail
        # => XYZ Consultancy Ltd
    
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