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Home/ Questions/Q 8904969
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T02:16:17+00:00 2026-06-15T02:16:17+00:00

I have following JSON saved in menu.json file: { menu: { menuitems: [ {

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I have following JSON saved in menu.json file:

       {
          "menu": {
                    "menuitems": [
                     {
                          "label": "Account",
                          "listview": "Account List"
                      },
                      {
                          "label": "Documents",
                          "listview": "Document List"
                      }
                                ]
                  }
       }

I have written this data to the file manually.I retrieve this data using following function:

        public ActionResult GetFromFile(string path)// path points to the menu.json file
       {
          StreamReader sr = new StreamReader(path);
          string filedata = sr.ReadToEnd();
          Menu menu = JsonSerializer.DeserializeToString<Menu>(filedata);
          return Json(menu, JsonRequestBehavior.Allowget);

       }

When I get the response as menu , I am not able to get it separated in the class fields. moreover, I have a single class and so how do I store my json file data to this class?? Will there be any modifications in the class structure? My Menu Class is as follows:

    public class Menu

    {
       public string Label {get;set;}
       public string Listview {get;set;}
   }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T02:16:18+00:00Added an answer on June 15, 2026 at 2:16 am

    The serialization has an extra, unnamed container above menu. Your class structure needs to look like:

    public class container
    {
        public menu menu { get; set; }
    }
    
    public class menu
    {
        public menuitem[] menuitems { get; set; }
    }
    
    public class menuitem
    {
        public string Label { get; set; }
        public string Listview { get; set; }
    }
    

    And to deserialize, you can use:

    JavaScriptSerializer js = new JavaScriptSerializer();
    StreamReader sr = new StreamReader("menu.json");
    string filedata = sr.ReadToEnd();
    var menus = js.Deserialize<container>(filedata);
    
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