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Home/ Questions/Q 7404709
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:17:39+00:00 2026-05-29T05:17:39+00:00

I have following main.xml of layout <LinearLayout xmlns:android=http://schemas.android.com/apk/res/android android:layout_width=fill_parent android:layout_height=fill_parent android:orientation=vertical > <TextView android:id=@+id/textview01

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I have following main.xml of layout

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >

<TextView
    android:id="@+id/textview01"
    android:layout_width="fill_parent"
    android:layout_height="wrap_content"
    android:text="@string/hello" />

and I am trying to retrieve the text i.e. @string/hello by using the following code

   public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);



  TextView tv= (TextView) findViewById(R.id.textview01);
  String input= tv.getText().toString();

  Log.d("Info",input);

but I am not able to see the output. Application is crashing with NULL Exception error at the String input = tv.getText(

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:17:40+00:00Added an answer on May 29, 2026 at 5:17 am

    You need to call

    setContentView(R.layout.main);
    

    before calling findViewById

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