Question

i have following php code which display company logo

     <?php
     $key=$_GET['key'];
     /// key process ///

     ////////////////////
     ?>
     <img src=images/logo.jpg" />

when i run this php file this show logo.jpg
but when i call this from

       <img src="../temp.php?key=123" width="438" height="100" />

it didn’t show image

actually what i want to track this image.

Thanks

Answer 1

If you want to use something like this :

Then temp.php should actually :

• send HTTP-headers for some image content-type
• and send the actual content of the image.
  • and not any HTML code

This is because the browser expects that the URL pointed to by the src attribute of the <img> tag actually corresponds to a valid image — and not some HTML text.

For instance, temp.php could contain something like this :

<?php
$key = $_GET['key'];
// TODO : security check on $key !!!
$file = 'images/logo-' . $key . '.jpg';
header('Content-type: image/jpeg');
readfile($file);
?>

As a couple of sidenotes :

• You must send the right Content-type HTTP header ; which means you must know if your image is a gif, jpeg, png, …
• You must check if $_GET['key'] is correct, to not send the content of an un-wanted file !
• There should be absolutly no white-space character before or after the <?php ... ?> tags : the only output must be the content of the image.