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Home/ Questions/Q 8627355
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T08:15:36+00:00 2026-06-12T08:15:36+00:00

I have following sample ( link to ideone ). long lDurationMillis = 0; lDurationMillis

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I have following sample (link to ideone).

long lDurationMillis =  0;
lDurationMillis = Long.parseLong("30000.1");
System.out.print("Play Duration:" + lDurationMillis);

It throws an exception:

Exception in thread "main" java.lang.NumberFormatException: For input string: "30000.1"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
at java.lang.Long.parseLong(Long.java:419)
at java.lang.Long.parseLong(Long.java:468)
at Main.main(Main.java:9)

But why it wont let me convert that number to a string directly ?I can convert number to integer and than convert to double . But is there any other way ?

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  1. Editorial Team
    Editorial Team
    2026-06-12T08:15:37+00:00Added an answer on June 12, 2026 at 8:15 am

    The value 30000.1 is an invalid long value. You could parse the double value first:

    lDurationMillis = (long)Double.parseDouble("30000.1");
    
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