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Home/ Questions/Q 6238409
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T11:12:31+00:00 2026-05-24T11:12:31+00:00

I have following script: it is creating tabs based on number of visible ‘li’

  • 0

I have following script:

  • it is creating tabs based on number of visible ‘li’
  • please note this is only the part of the script – I’m looking for shorthans – smart ideas to write that etc..

Can you suggest any shorthand for this? Or more elegant way to write that? Any suggestion much appreciated.

    var CoundNumberOfDivs = $('#portfolio-items li:visible').length;

    if( CoundNumberOfDivs <= 4 ) { 
        $('.pagination li a').hide(); 
        return false;
    }
    else if( CoundNumberOfDivs <= 8 ) { 
        $('.pagination li a').hide();
        $('.pagination li a:lt(2)').show(); 

        $('#portfolio-items li').hide();
        $('#portfolio-items li:lt(4)').show();
    }
    else if( CoundNumberOfDivs <= 12 ) { 
        $('.pagination li a').hide();
        $('.pagination li a:lt(3)').show(); 

        $('#portfolio-items li').hide();
        $('#portfolio-items li:lt(4)').show();
    }
    else if( CoundNumberOfDivs <= 16 ) { 
        $('.pagination li a').hide();
        $('.pagination li a:lt(4)').show();

        $('#portfolio-items li').hide();
        $('#portfolio-items li:lt(4)').show(); 
    }
    else if( CoundNumberOfDivs <= 20 ) { 
        $('.pagination li a').hide();
        $('.pagination li a:lt(5)').show();

        $('#portfolio-items li').hide();
        $('#portfolio-items li:lt(4)').show(); 
    }

    else if( CoundNumberOfDivs <= 24 ) { 
        $('.pagination li a').hide();
        $('.pagination li a:lt(6)').show();

        $('#portfolio-items li').hide();
        $('#portfolio-items li:lt(4)').show(); 
    }

    else if( CoundNumberOfDivs <= 28 ) { 
        $('.pagination li a').hide();
        $('.pagination li a:lt(7)').show();

        $('#portfolio-items li').hide();
        $('#portfolio-items li:lt(4)').show(); 
    }

    else if( CoundNumberOfDivs <= 32 ) { 
        $('.pagination li a').hide();
        $('.pagination li a:lt(8)').show();

        $('#portfolio-items li').hide();
        $('#portfolio-items li:lt(4)').show(); 
    }

    else if( CoundNumberOfDivs <= 36 ) { 
        $('.pagination li a').hide();
        $('.pagination li a:lt(9)').show();

        $('#portfolio-items li').hide();
        $('#portfolio-items li:lt(4)').show(); 
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T11:12:33+00:00Added an answer on May 24, 2026 at 11:12 am

    This is untested, but it looks at first glance that it would work. Instead of all your else if statements, I just use one, and divide CoundNumberOfDivs by 4, round it up, and use that in the :lt part of the selector:

    var CoundNumberOfDivs = $('#portfolio-items li:visible').length;
    $('.pagination li a').hide(); 
    if( CoundNumberOfDivs <= 4 ) { 
        return false;
    }
    else {
        var num = Math.ceil(CoundNumberOfDivs / 4);
        $('.pagination li a:lt(' + num + ')').show(); 
        $('#portfolio-items li').hide();
        $('#portfolio-items li:lt(4)').show();
    }
    

    I’ve also moved the $('.pagination li a').hide(); line outside of the if because it’s duplicated in your if and all of the else ifs.

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