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Home/ Questions/Q 3276960
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T19:19:03+00:00 2026-05-17T19:19:03+00:00

I have, for example, such class: class Base { public: void SomeFunc() { std::cout

  • 0

I have, for example, such class:

class Base
{
   public: void SomeFunc() { std::cout << "la-la-la\n"; }
};

I derive new one from it:

class Child : public Base
{
   void SomeFunc()
   {
      // Call somehow code from base class
      std::cout << "Hello from child\n";
   }
};

And I want to see:

la-la-la
Hello from child

Can I call method from derived class?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T19:19:03+00:00Added an answer on May 17, 2026 at 7:19 pm

    Sure:

    void SomeFunc()
    {
      Base::SomeFunc();
      std::cout << "Hello from child\n";
    }
    

    Btw since Base::SomeFunc() is not declared virtual, Derived::SomeFunc() hides it in the base class instead of overriding it, which is surely going to cause some nasty surprises in the long run. So you may want to change your declaration to

    public: virtual void SomeFunc() { ... }
    

    This automatically makes Derived::SomeFunc() virtual as well, although you may prefer explicitly declaring it so, for the purpose of clarity.

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