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Home/ Questions/Q 6916135
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T09:33:48+00:00 2026-05-27T09:33:48+00:00

I have found a bit of code in MATLAB: y = fft(y, nfft); Where

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I have found a bit of code in MATLAB:

y = fft(y, nfft);

Where y is a 512×443 two-dimensional array and nfft = 512.

I thought that fft is for a one-dimensional array and for a two-dimensional array there should be fft2, but fft is working. How is that possible?

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  1. Editorial Team
    Editorial Team
    2026-05-27T09:33:49+00:00Added an answer on May 27, 2026 at 9:33 am

    From the documentation (emphasis mine):

    Y = fft(x) returns the discrete Fourier transform (DFT) of vector x, computed with a fast Fourier transform (FFT) algorithm.

    If the input X is a matrix, Y = fft(X) returns the Fourier transform of each column of the matrix.

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