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Asked: May 11, 20262026-05-11T02:31:25+00:00 2026-05-11T02:31:25+00:00

I have found a problem with use JQuery timeout, i have a page with

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I have found a problem with use JQuery timeout, i have a page with script, it’s set a timeout and waiting response from server. The problem is when timeout have to perform, in short words, it ‘no action’. I think that script not interrupt the connection with server and wait for server response, because in server side the connection is on for 10 sec (but timeout is set 5 sec). I see this problem when server work in different domain name then client, whereas when the server and client work in local this problem there isn’t.

Have you a idea because this error happened or how to close the Script connection?

// client   $.ajax({      type: 'GET',      url: 'some.php',      data: 'name=John&location=Boston',      timeout: 5000,      success: function(msg){          alert( 'Data Saved: ' + msg );      },     error: function(request, errorType, errorThrown){          alert('opppsssss .... ');     } }); 

and the server code:

//some.php  < ?  //simulate long task  sleep(10); //sleep 10 seconds  //send response  echo 'some test data';  ? > 

Best Regards

Domenico

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  1. 2026-05-11T02:31:26+00:00Added an answer on May 11, 2026 at 2:31 am

    You’re doing it back-to-front by the looks of it. You’ve set the timeout to 5000 milliseconds (5 seconds) so if the server-side code takes longer to respond than 5 seconds it will timeout. You’re doing sleep(10); which sleeps for 10 seconds, which is twice as long as the specified timeout. The way to fix this would be to do the following:

    // client  $.ajax({     type: 'GET',     url: 'some.php',     data: 'name=John&location=Boston',     timeout: 10000,      success: function(msg){         alert( 'Data Saved: ' + msg );     },     error: function(request, errorType, errorThrown){         alert('opppsssss .... ');     } }); 

    And the server code:

    //some.php < ?     //simulate long task     sleep(5); // sleep 5 seconds!     //send response     echo 'some test data'; ? > 

    Hopefully that helps.

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