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Home/ Questions/Q 7866767
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T00:30:05+00:00 2026-06-03T00:30:05+00:00

I have found the following regular expression new RegExp((^|\\s)hello(\\s|$)); I refer http://www.javascriptkit.com/jsref/escapesequence.shtml for regular

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I have found the following regular expression

new RegExp("(^|\\s)hello(\\s|$)");

I refer http://www.javascriptkit.com/jsref/escapesequence.shtml for regular expressions..
But i cannot see \s escape sequence there..I know \s indicate whitespace character…
But what does the preceding \ do ..Which character is escaped?
I found similar regular expression in the Treewalker code in the following document http://ejohn.org/blog/getelementsbyclassname-speed-comparison/

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  1. Editorial Team
    Editorial Team
    2026-06-03T00:30:07+00:00Added an answer on June 3, 2026 at 12:30 am

    The double \\ is to escape the backslash inside the string. In other word, \\ will be interpreted as \ for the regular expression.

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