Question

I have found this script that expand image when mouse is over, but when click the image, open the image in a new page.

I would like modify the script because I don’t want that image open in new page when click.

How I can modify the script to not open the photo in new page?

This is the script:

this.imagePreview = function(){ 
    /* CONFIG */

        xOffset = 10;
        yOffset = 30;

        // these 2 variable determine popup's distance from the cursor
        // you might want to adjust to get the right result

    /* END CONFIG */
    $("a.preview").hover(function(e){
        this.t = this.title;
        this.title = "";    
        var c = (this.t != "") ? "<br/>" + this.t : "";
        $("body").append("<p id='preview'><img src='"+ this.href +"' alt='Image preview' />"+ c +"</p>");                                
        $("#preview")
            .css("top",(e.pageY - xOffset) + "px")
            .css("left",(e.pageX + yOffset) + "px")
            .fadeIn("fast");                        
    },
    function(){
        this.title = this.t;    
        $("#preview").remove();
    }); 
    $("a.preview").mousemove(function(e){
        $("#preview")
            .css("top",(e.pageY - xOffset) + "px")
            .css("left",(e.pageX + yOffset) + "px");
    });         
};


// starting the script on page load
$(document).ready(function(){
    imagePreview();
});

To see the demo: http://cssglobe.com/lab/tooltip/02/

Thanks

Regards

Answer 1

$('a.preview').click({
    function (event) {
        event.preventDefault();
    });

To have all previews to occur at the same position, change the coordinates in these lines

.css("top",(e.pageY - xOffset) + "px")
.css("left",(e.pageX + yOffset) + "px")

Write the coordinate that you want in place of e.pageY - xOffset and e.pageX + yOffset