Question

I have four IF statements, is it possible to rewrite this into a neater loop, where the [i] may be ‘4’ or higher.

if (typed.length == 1 && c.charAt(0) == typed[0]) { 
    //something ; 
    return false;
}

if (typed.length == 2 && c.charAt(0) == typed[0] 
    && c.charAt(1) == typed[1]) {  
    //something ; 
    return false;
}

if (typed.length == 3 && c.charAt(0) == typed[0] 
    && c.charAt(1) == typed[1] && c.charAt(2) == typed[2]) {  
    //something ; 
    return false;
}

if (typed.length == 4 && c.charAt(0) == typed[0] 
    && c.charAt(1) == typed[1] && c.charAt(2) == typed[2] 
    && c.charAt(3) == typed[3]) {  
    //something ; 
    return false;
}

Answer 1

Looks to me like something like this should to it:

if (c.substr(0, typed.length) == typed)

Possibly typed.join() if typed is an array.