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Home/ Questions/Q 6089383
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T12:05:38+00:00 2026-05-23T12:05:38+00:00

I have: function getRandomInt(min, max){ return Math.floor(Math.random() * (max – min + 1)) +

  • 0

I have:

function getRandomInt(min, max){
        return Math.floor(Math.random() * (max - min + 1)) + min;
}

But the problem is I want randomise the population of something with elements in an array (so they do not appear in the same order every time in the thing I am populating) so I need to ensure the number returned is unique compared to the other numbers so far.

So instead of:

   for(var i = 0; i < myArray.length; i++) {

   }

I have:

var i;
var count = 0;
while(count < myArray.length){
  count++;
  i = getRandomInt(0, myArray.length); // TODO ensure value is unique

  // do stuff with myArray[i];
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T12:05:39+00:00Added an answer on May 23, 2026 at 12:05 pm

    It looks like rather than independent uniform random numbers you rather want a random permutation of the set {1, 2, 3, …, N}. I think there’s a shuffle method for arrays that will do that for you.


    As requested, here’s the code example:

    function shuffle(array) {
      var top = array.length;
      while (top--) {
          var current = Math.floor(Math.random() * top);
          var tmp = array[current];
          array[current] = array[top - 1];
          array[top - 1] = tmp;
        }
      return array;
    }
    
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