Question

I have function that is sourced through the .bashrc file on remote host A.
If i use “which” on remote host A , i`m getting function body as output.
I need to run it through ssh remotely from another host B.
Currently , all my tries are ending with “command not found error”.
I already tried to pass to

ssh A  "source /home/user/.bashrc && function "  

, this not help.
Also tried force ssh to assing pseudo-tty with -t key. SHELL on both hosts is bash.
ssh localhost on host A still keeps function status available.

Output :

[user@hostA ~]$ which status
status is a function
status ()
{
    dos -s $*
}


[user@hostB ~]$ ssh hostA " source  /home/user/deploy/bin/_bashrc && status all "
ls: : No such file or directory
bash: status: command not found

Answer 1

Basically, you can’t. To do that you need to copy the sourced file on the remote host and source it in there. Note, that your file may be sourcing in some other files as well… This is almost like running local program on the remote host.