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Home/ Questions/Q 6374599
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T01:30:28+00:00 2026-05-25T01:30:28+00:00

I have function where I read from a mysql table a set of value.

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I have function where I read from a mysql table a set of value. Part of my codes is like this. The problem why I need to use fully php here is this a ajax called page.

echo "<tr id='gridRow'>
 <td >$count</td>
 <td> <input type='checkbox' onClick=selectAndUpdate('$row1[size]')></td>
 <td> {$row1[SerialNo]}</td> 
 <td> {$row1[InHouseBranding]}</td> 
 <td> {$row1[BrandCode]}</td> 
 <td> {$row1[size]}</td> 
 <td> {$row1[Pattern]}</td>  
 <td> {$row1[EntryStatus]}</td>   
 </tr>";

A sample row generated is as below can you notice this line why the same value appear properly in the 21060R 22.567 but in the previous line is showing me like this 22.567′)=”” onclick=”selectAndUpdate(‘21060R”> any idea?

<tr id="gridRow">
<td>1</td>
<td>
<input type="checkbox" 22.567')="" onclick="selectAndUpdate('21060R">
</td>
<td> EA12</td>
<td> BOR1</td>
<td> GY</td>
<td> 21060R 22.567</td>
<td> HMG 2020</td>
<td> New</td>
</tr>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T01:30:30+00:00Added an answer on May 25, 2026 at 1:30 am

    The generated code seems unrelated to the code the echo produces, notice int the echo it is written type='checkbox' while in the output its type="checkbox" (notice the quotes). make sure that you suspect the right echo to be wrong.

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