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Home/ Questions/Q 7630491
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T06:07:10+00:00 2026-05-31T06:07:10+00:00

I have $.getJSON(‘json.ashx?mode=Gender’, function (data) { memberInfo = data[1]; options.series = data; originalData =

  • 0

I have

    $.getJSON('json.ashx?mode=Gender', function (data) {
            memberInfo = data[1]; 
            options.series = data;
            originalData = data[0];
            ...
            ...
    });

which returns

[
{"type" : "pie","name" : "Gender",
"data" : [["Male",32],["Female",11]]},
{"A123":"F","A223":"M","A423":"F","A332":"M","B327":"F"}
]

and

    function calcOptionsData() {   
    ...    
    var maleCount = 0;
    var femaleCount = 0;       
    ...              
    ...
    $.each(val, function(index, item) {
        if (memberInfo[item] == 'M')                    
            maleCount += 1;

        if (memberInfo[item] == 'F')                    
            femaleCount += 1;
    });

    options.series[0].data[0][1] = originalData.data[0][1];
    options.series[0].data[1][1] = originalData.data[1][1];

    if (radioBttnClicked == 'Gender')
    {

        options.series[0].data[0][1] += maleCount;

        options.series[0].data[1][1] += femaleCount;
    }
} 

I want every times the calcOptionsData() called the originalData resets the options.series[0].data to the value originally generated from the getJSON. The current code mirrors originalData with options.series[0].data.

Thanks,

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T06:07:12+00:00Added an answer on May 31, 2026 at 6:07 am

    You may use $.extend(true, {}, originalObject) to create an independent deep copy of a JSON object.

    Then you may use this copy for any purpose without affecting the original object.

    See the docs for more information.

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