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Home/ Questions/Q 7765501
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T15:10:54+00:00 2026-06-01T15:10:54+00:00

I have got a module, where, when a user clicks on a link, I

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I have got a module, where, when a user clicks on a link, I am loading a new form in a dialog, which has an Ajax-enabled submit button. In my dialog, I don’t want the entire drupal header and footer, etc., to display. All I am displaying is, the contents of that new form. So my form is outputted via json like this:

$json['html'] = drupal_render(drupal_get_form('my_form'));
drupal_json_output($json); 

Which works like I want, and only the form contents are displayed. However, when this happens, the submit button in that form, which is ajax-enabled, doesn’t submit through ajax. Instead, it submits like a normal button and takes me to the same form on another page.

If I have the form being outputted and displayed normally, with the header and footers, like this:

$output = drupal_get_form('my_form');
return $output;

everything works just fine, and my submit button is ‘ajax-enabled’.

I thought, maybe it was because I was loading the new content and the behaviors were not being attached to the these new form contents. So in my js file, I did this as well:

$('a.my_link', context).click(function() {
//processing done here
$('#my_modal_dialog').html(jsondata['html']);
}, "json");
Drupal.attachBehaviors($('#my_modal_dialog'));

That little addition, didn’t fix the problem either. I am wondering as to why, if the form is outputted normally the button works as an ajax button, and when, only the form content is displayed, the ajax doesn’t work.

Hoping someone will have the answer…Thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T15:10:55+00:00Added an answer on June 1, 2026 at 3:10 pm

    I have got the problem solved and it can be found in the following link: drupal.org/node/1517414.

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