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Asked: 2026-06-07T05:17:29+00:00

I have got a page with data generated client-side that is formatted as a

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I have got a page with data generated client-side that is formatted as a fifteen column array. The number of rows will vary based on user input, anywhere between 1 and 200 total. I want to pass this array to my server in an efficient manner where it will be inserted into a MySQL database using php, but I don’t know how the data should be packaged for transport. The data in the page is generated using JavaScript and is laid out in this fashion:

<div id="row1" class="row">
  <span id="entry1">User generated data.</span>
  <span id="entry2">User generated data.</span>
  <span id="entry3">User generated data.</span>
  ...
  <span id="entry15">User generated data.</span>
</div>
<div id="row2" class="row">
  <span id="entry1">User generated data.</span>
  <span id="entry2">User generated data.</span>
  <span id="entry3">User generated data.</span>
  ...
  <span id="entry15">User generated data.</span>
</div>

Recommendations anyone?

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1 Answer

  1. Editorial Team

    I don’t think it is canon to repeat the same ID multiple times.

    <div id="row1" class="row">
  <span id="entry1">User generated data.</span>
  <span id="entry2">User generated data.</span>
  ...
<div id="row2" class="row">
  <span id="entry1">User generated data.</span>

    I’d use compound IDs:

    <div id="row1" class="row">
  <span id="entry1_1">User generated data.</span>
  <span id="entry1_2">User generated data.</span>
  ...
<div id="row2" class="row">
  <span id="entry2_1">User generated data.</span>
  ...

    At that point you can:

    • build a POST query with all items as key/values:
      entry1_1=User generated data.
      …

      which will be easily parseable by PHP, or:

    • build a JSON string in Javascript as a dict of dicts
      { row1: { entry1: “User generate data” }, row2: {…}

    • you might try to preparse the array for PHP by submitting fields
      like this:

      entry[1][1]=User generated data.

      ( “entry[1][1]” is the name of the key. PHP should parse it correctly).

    You could also, depending on how you create new items, directly create a POST FORM, appending fields like this to the DOM:

    <input type="text" name="entry[7][14]" value="" class="input" />

    Sorry, but without a better idea of your interaction design, it is awkward to make suggestions.

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