Question

I have got a small problem with 1D array in c++. I have got a function line this:

void func(int (&array)[???])
{
    // some math here;

    "for" loop {
        array[i] = something;
    }
}

I call the functions somewhere in the code, and before I made math I’m not able to know dimension of the array. The array goes to the function as a reference!, because I need it in the main() function. How I can allocate array like this?, so array with ?? dimension goes to the function as reference then I have to put the dimension and write to it some values.

Answer 1

Use a pointer, not a reference:

void func(int *a, int N);

Or, easier, use a vector:

void func(std::vector<int> &a);

Vectors can be allocated by simply saying

std::vector<int> a(10);

The number of elements can be retrieved using a.size().