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Home/ Questions/Q 6640475
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T23:40:37+00:00 2026-05-25T23:40:37+00:00

I have got below code in VBScript: <% Option Explicit #importXSLT tcm:228-190529-2048 As expandXSLT

  • 0

I have got below code in VBScript:

<%

Option Explicit  

#importXSLT "tcm:228-190529-2048" As expandXSLT
#importXSLT "tcm:228-642694-2048" As renderXSLT

Dim xml, currentDateTime

Set xml = getNewDomDocument()
xml.loadXML TDSE.GetListPublications(3)

expandXSLT.input = xml
Call expandXSLT.addParameter("publication", Component.Publication.Id)
expandXSLT.transform

xml.loadXML(expandXSLT.output)
'WriteOut xml.xml

currentDateTime = now
renderXSLT.input = xml
Call renderXSLT.addParameter("currentPublishedDate", currentDateTime)
renderXSLT.transform

WriteOut renderXSLT.output

Set xml = Nothing

%>

You can see there is two syntax where I am adding the XSLT parameter, the first one is working fine i.e.

expandXSLT.input = xml
Call expandXSLT.addParameter("publication", Component.Publication.Id)
expandXSLT.transform

However the new requirement was that, we need to send current date time from here to the XSLT, so I have added the same logic to send the current date & time to my XSLT, below is code added by me

 currentDateTime = now
    renderXSLT.input = xml
    Call renderXSLT.addParameter("currentPublishedDate", currentDateTime)
    renderXSLT.transform

But when I am trying to run the above code its giving below error:

Type mismatch.
(source: Call renderXSLT.addParameter(“publishedDate”, currentDateTime)).

Please suggest!!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T23:40:38+00:00Added an answer on May 25, 2026 at 11:40 pm

    Try whether converting the currentDateTime value you have to a string first to pass that string to XSLT e.g. CStr(currentDateTime).

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