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Home/ Questions/Q 531561
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T09:18:49+00:00 2026-05-13T09:18:49+00:00

I have got simple query WITH conn_cte ( ParentCategoryId, CategoryId, IdsPath ) AS (

  • 0

I have got simple query

WITH  conn_cte ( ParentCategoryId, CategoryId, IdsPath )
        AS ( SELECT ParentCategoryId
                   ,CategoryId
                   ,CAST(ParentCategoryId AS varchar(1000))
             FROM   Ind_CategoriesConnections
             WHERE  ParentCategoryId = 0
             UNION ALL
             SELECT cc.ParentCategoryId
                   ,cc.CategoryId
                   ,CAST(IdsPath + ','
                    + CAST (cc.ParentCategoryId AS varchar(5)) AS varchar(1000))
             FROM   Ind_CategoriesConnections AS cc
                    INNER JOIN conn_cte AS conn ON conn.CategoryId = cc.ParentCategoryId
                                                   AND cc.categoryid NOT IN (
                                                   SELECT conn.Categoryid )
           )
  SELECT  x.*
  FROM    ( SELECT  t.ParentCategoryId
                   ,t.CategoryId
                   ,t.IdsPath + ',' + CAST(t.CategoryId AS varchar(5)) AS [path]
            FROM    conn_cte t
                    INNER JOIN Ind_Categories c ON t.CategoryId = c.CategoryId
                                                   AND c.CategoryViewId = 1
                                                   AND c.IsActiveYN = 1
          ) x
  ORDER BY x.path

I am interesting in query (optimal) that only return full paths from root to leaf.

for example the part of result is

Parent  Child   Path
12       16     0,8,12,16
16       17     0,8,12,16,17
17       18     0,8,12,16,17,18
17       19     0,8,12,16,17,19

zero is root 18,19 are leafs (and children), I want to ignore partly paths like 0,8,12,16 and 0,8,12,16,17 and get only full paths (ended with leafs)
0,8,12,16,17,18 and 0,8,12,16,17,19

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  1. Editorial Team
    Editorial Team
    2026-05-13T09:18:50+00:00Added an answer on May 13, 2026 at 9:18 am

    You could say something like:

    WHERE NOT EXISTS (SELECT * FROM conn_cte AS parents WHERE t.path LIKE parents.path + '%')
    
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