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Home/ Questions/Q 6906511
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T08:19:11+00:00 2026-05-27T08:19:11+00:00

I have group definitions in an XML schema. Like so: <attributeGroup name=my_attributes> <attribute ref=ns:foo

  • 0

I have group definitions in an XML schema. Like so:

<attributeGroup name="my_attributes">
    <attribute ref="ns:foo" />
    <attribute ref="ns:bar" />
</attributeGroup>

Also, I have an XML transformation, in which I want to be able to reuse these definitions. Is it possible to create a template that matches such a group? Something like this maybe:

<xsl:template matchGroup="my_attributes">
    <foobar>
        <xsl:copy-of select="@*"/>
        <xsl:value-of select="." />
    </foobar>
</xsl:template>
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  1. Editorial Team
    Editorial Team
    2026-05-27T08:19:11+00:00Added an answer on May 27, 2026 at 8:19 am

    Is it possible to create a template that matches such a group?
    Something like this maybe:

    <xsl:template matchGroup="my_attributes"> 
        <foobar> 
            <xsl:copy-of select="@*"/> 
            <xsl:value-of select="." /> 
        </foobar> 
    </xsl:template>
    

    No, the XSLT <xsl:template> instruction doesn’t have a matchGroup attribute and
    any compliant XSLT processor must raise a syntax error for this reason
    .

    Something like this is probably close to what you are looking for:

    <xsl:template match="@ns:foo[../@ns:bar]">
     <!-- Processing here -->
    </xsl:template>
    

    The meaning of the match pattern above:

    Match any attribute with local-name() foo that is in the namespace to which the prefix "ns:" is associated, and whose “parent” (the ellement this attribute is attached to) *has also another attribute that is named* ns:bar.

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