Question

I have hard time understanding the following code buffer[i] = arr ? arr[i] : 0;.
Does this mean that if arr contain any thing then its equal to buffer[i] and if it doesn’t it equals to 0?

#include <iostream>
using namespace std;
int main ()
{
    int arr[5]={11,22,33,44,55};
    int * buffer;
    buffer = new int [5];

    for(int i=0;i<5;i++){
        buffer[i] = arr ? arr[i] : 0;//true/falls
        cout<<buffer[i]<<",";
    }
    cout<<endl;

    int arr2[5]={};
    int * buffer2;
    buffer2 = new int [5];

    for(int i=0;i<5;i++){
        buffer2[i] = arr2 ? arr2[i] : 0;//true/falls
        cout<<buffer2[i]<<",";
    }
    cout<<endl;
}

Answer 1

It seems the code may have been ported from when arr was allocated dynamically. Now it’s on the stack so arr can never be NULL and so the check is useless