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Home/ Questions/Q 6801625
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:07:22+00:00 2026-05-26T19:07:22+00:00

I have hibernate query as below: String mySql = SELECT S.col1, S.col2, T.col3, T.col4,

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I have hibernate query as below:

String mySql = "SELECT S.col1, S.col2, T.col3, T.col4, T.col5 
                FROM myTable S, myTable1 T 
                WHERE S.id = :id and S.id = T.id";
Query myQuery = this.em.createQuery(mySql);
myQuery.setParameter("id", "123");
List<Object> result = myQuery.getResultList();

Table myTable and myTable1 are entity classes.

myTO is a simple java class with properties col1, col2, col3, col4, col5.

The result of above query should be mapped to the properties of myTO.

How do I iterate the columns in result ? Or am I retrieving the result incorrectly ?

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:07:23+00:00Added an answer on May 26, 2026 at 7:07 pm

    It seems you’re trying to query a subset of the table’s columns. For this you can use this example from Hibernate documentation:

    11.4.1.2. Queries that return tuples

    Hibernate queries sometimes return tuples of objects. Each tuple is returned as an array:

    Iterator kittensAndMothers = sess.createQuery(
                "select kitten, mother from Cat kitten join kitten.mother mother")
                .list()
                .iterator();
    
    while ( kittensAndMothers.hasNext() ) {
        Object[] tuple = (Object[]) kittensAndMothers.next();
        Cat kitten = (Cat) tuple[0];
        Cat mother = (Cat) tuple[1];
         ....
    }
    

    If you don’t have a problem to retrieve the whole entity (or at least its first level simple properties) you can just use:

    List<Cat> cats = session.createQuery(
        "from Cat where cat.name = ?")
        .setString(0, name)
        .list();
    for ( Cat cat : cats ) {
        Cat mother = cat.getMother();
        ...
    }
    
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