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Home/ Questions/Q 8603839
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T02:25:08+00:00 2026-06-12T02:25:08+00:00

I have hosted my websocket server using python tornado server on localhost ws://localhost:8001 and

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I have hosted my websocket server using python tornado server on localhost ws://localhost:8001 and client is on another system on 192.168.0.116 so when we try to communicate it works fine but cant debug it using wireshark.
My websocket is running on port 8001 so i tried using

tcp.port==8001

but no result found so i then tried it on http
my ip in lan is 192.168.0.219 and port 8001. so

http.host == 192.168.0.219 && tcp.port == 8001

but no results found.
Is there anything else that i can try to debug my websocket.

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  1. Editorial Team
    Editorial Team
    2026-06-12T02:25:09+00:00Added an answer on June 12, 2026 at 2:25 am

    Finally i found it.

    When i put

    tcp.dstport == 8001 || tcp.srcport == 8001
    

    At that time i can capture it.

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