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Home/ Questions/Q 7163397
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T13:53:48+00:00 2026-05-28T13:53:48+00:00

I have html like this: <div> <input type=checkbox id=checkbox, checked=checked/> <label for=checkbox>Copy values</label> </div>

  • 0

I have html like this:

<div>
    <input type="checkbox" id="checkbox", checked="checked"/>
    <label for="checkbox">Copy values</label>
</div>
<div>
    <input id="source" type="text"/>
</div>
<div>    
    <input id="target" type="text"/>
</div>

And I’m trying to implement jQuery code to copy value from source input to target one, only when the checkbox is checked. Here’s my code:

var checkbox = $("#checkbox");
var source = $("#source");
var target = $("#target");

var bindFunction = function () {
    var copyValue = function () {console.log("asd");
        target.val(source.val());
    }
    if (checkbox.is(":checked")) {
        source.bind("keyup", copyValue);
    }
    else {
        source.unbind("keyup", copyValue);
    }    
}
checkbox.bind("change", bindFunction);
bindFunction();

However, it does not work as expected – for some reason the copyValue function doesn’t get unbound. What am I doing wrong?

Here’s a jsFiddle.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T13:53:49+00:00Added an answer on May 28, 2026 at 1:53 pm

    You need to move the copyValue function outside of the bindFunction function.

    This is because it was creating a new instance of copyValue each time the checkbox was clicked so the unbind was running against a different function than the one that was originally bound.

    var copyValue = function () {
        console.log("asd");
        target.val(source.val());
    }
    
    var bindFunction = function () {        
        if (checkbox.is(":checked")) {
            source.bind("keyup", copyValue);
        }
        else {
            source.unbind("keyup", copyValue);
        }    
    }
    checkbox.bind("change", bindFunction);
    bindFunction();
    

    http://jsfiddle.net/5b93H/1/

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