Question

I have images in an array and I want them to be display in a table with 3 columns!

So obviously in HTML, it is like:

<table>
    <tr>
        <td><img src="image1.jpg"></td>
        <td><img src="image2.jpg"></td>
        <td><img src="image3.jpg"></td>
    </tr>
    <!-- and so on... -->
</table>

So I want it to print out in PHP but the problem is the code.

My code is like this:

    $photos = array(     "image1",
                        "image2",
                        "image3",
                        "image4",
                        "image5",
            );
    foreach ($photos as $photo) {
        $i = 0;
        if ($i < 3) {
            echo '<td><center><img src="'.$photo.'.jpg"></td>';
            $i++;
        } elseif ($i == 3) {
            echo '</tr><tr>';
            $i = 0;
        }
    }

I don’t know what seems to be the problem and every time I echo out the variable $i, it echoes out like 11111111111111111111111111111111111111111111.

Answer 1

change this

foreach ($photos as $photo) {
        $i = 0;

to

$i = 0;
foreach ($photos as $photo) {