Question

I have implemented a function u() that can transfer the result from servers to the outside so that I can do something out of the success:function(). However, I don’t know how to get the result “y” from _pass. I have tried _pass.y but got an error message.
Also, “y” was successfully assigned.

var _pass = {};
_pass = function(y) {
    alert(y);
    return y;
};

function u(pass) {
    $.ajax({
        /* ... */

        success: function(html,pass) {
            pass(html);
        }
});}

Answer 1

Try this:

var _pass = {};
_pass = function(y) {
    console.log(y);
    return y;
};

function u(pass) {
    var methodName = pass;

    $.post(location.href, function(data) {
        methodName(data);
    });

}
u(_pass);

http://jsfiddle.net/nZnFM/8/