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Home/ Questions/Q 235085
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T20:14:14+00:00 2026-05-11T20:14:14+00:00

I have implemented a shared library in Linux and try to test it, but

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I have implemented a shared library in Linux and try to test it, but I get an error “undefined reference to `CEDD(char*)'”.

I use Eclipse with following parameters:

  • Path to include files (here is
    everything ok)
  • Path to the library
    and its name. Path is correct and the
    name is WISE_C (full name:
    libWISE_C.so)

My Code:

Test programm I use for tests:

#include <iostream>
#include <Descriptor.h>

int main() {
    char* path = "/export/home/pdmazubi3/workspace/proj1/src/pic.jpg";
    double * cedd = CEDD(path); /////   <-ERROR!

    std::cout << "!!!Hello World!!!" << cedd[1];
    return 0;

}

Header Descriptor.h:

double* CEDD(char* path);

A part of Descriptor.c with desirable function:

#include "Descriptor.h"
#include "highgui.h"
#include "cv.h"

double* CEDD(char* path)
{
    IplImage* srcImg;
    IplImage* ImageGrid;
...
}

What I am doing wrog? I have raed a lot of articles in the Internet but I didn’t found a solution.

undefined reference to `CEDD(char*)’ is a compiler or linker error?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T20:14:15+00:00Added an answer on May 11, 2026 at 8:14 pm

    It’s a linker error (although I don’t think it usually includes the ‘char*’ bit), so it seems that it either cannot find your library or the library does not contain the function. The latter might also mean that it does contain the actual function, but with a different name; make sure both projects a compiled as C and not C++.

    Edit: I missed that you program is C++ (which also explains the more detailed linker message). In this case you should add extern "C" (conditionally, so it is only used when using C++) to the declaration of CEDD if the library is in C.

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