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Home/ Questions/Q 9298897
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T22:26:03+00:00 2026-06-18T22:26:03+00:00

I have implemented this d3 visualization http://bl.ocks.org/4745936 , to be loaded with dynamic data

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I have implemented this d3 visualization http://bl.ocks.org/4745936 , to be loaded with dynamic data instead of a .tsv

in my case, once my server passes new information to the selector, a second chart gets rendered under the first one, instead of modifying the contents of the existing graph.

I believe it has to do with this append method.

var svg = d3.select(selector).append("svg")
    .attr("width", width + margin.left + margin.right)
    .attr("height", height + margin.top + margin.bottom)
    .append("g")
    .attr("transform", "translate(" + margin.left + "," + margin.top + ")");

so I tried adding other exit().remove() methods to legend and cities variables right after they append('g'); but my javascript console says the exit() method does not exist at that point.

I feel I have the completely wrong approach, how do I update an existing graph like this? Having a second and third graph get generated alongside the previous ones is not the outcome I wanted at all

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  1. Editorial Team
    Editorial Team
    2026-06-18T22:26:05+00:00Added an answer on June 18, 2026 at 10:26 pm

    I was able to solve this problem with some jQuery and CSS voodoo

    basically since my d3 graph adds an svg element to an existing selector (a div in my case), I was able to check for the name of this dynamically

    var svgtest = d3.select(selector+" > svg"); getting the svg subchild element of that div. then I could use jquery to remove that element from the dom completely, and then let d3 continue running and append svg’s all it wants!

     var svgtest = d3.select(selector+" > svg");
        if(!svgtest.empty())
        {
            $(selector+" > svg").remove();
        }
    
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