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Home/ Questions/Q 4543212
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T15:29:58+00:00 2026-05-21T15:29:58+00:00

I have information in a table like so: id name recommender 1 daniel steve

  • 0

I have information in a table like so:

id    name    recommender
 1    daniel  steve
 2    daniel  tony
 3    steve   daniel

and this code:

<h2>Follow/Join Recommendation League Table</h2>
<br/>
<?php

$query = "SELECT name_of_follower, COUNT(name) FROM recommendation_competition_entrants GROUP BY name_of_follower ORDER BY COUNT(name) DESC"; 

$result = mysql_query($query) or die(mysql_error());

// Print out result
while($row = mysql_fetch_array($result)){
        echo $row['name_of_follower'] . " has ". $row['COUNT(name)'] . " entries.";
        echo "<br />";
}

?>

This counts all entries in the ‘name’ column and displays a mini league table which looks like this:

daniel - 2 entries
steve - 1 entry

What I need to do now is count names from both the name & recommender columns so the table would look like this:

daniel - 3 entries
steve - 2 entries
tony - 1 entry

Is there a simple way to do this?

Thanks for any help

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T15:29:59+00:00Added an answer on May 21, 2026 at 3:29 pm
    select name_of_follower, 
           count(name_of_follower) 
      from ( select name as name_of_follower 
              from abc 
             union all 
            select follower as name_of_follower  
              from abc
           ) t
     group by t.name_of_follower 
     order by count(name_of_follower) desc
    
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