Question

I have installed ConsoleExport Firebug extension. I have enabled auto-export feature at about:config by setting extensions.firebug.consoleexport.active to true. I have opened a page with JavaScript error, for example http://www.random.org. I have enabled Firebug, reloaded the page. I can see the error in log:

uncaught exception: Error: Permission denied for <https://www.facebook.com> to get property Proxy.InstallTrigger

The ConsoleExport page says:

You can also activate an auto-export feature that is sending
individual logs into specified server as XML packets.

I know I should set extensions.firebug.consoleexport.serverURL to server URL. I do not know how to catch XML packets that ConsoleExport sends.

For example, I know how to set up Apache on Mac, but what then? How to catch XML packets?

Environment:

• Mac OS X 10.7.2
• Firefox 8.0.1
• Firebug 1.8.4
• ConsoleExport 0.5b4

I have access to Windows and Linux machines, if the server that catches XML packets is easier to set up there.

Answer 1

Modified script fixing a problem with getting the posted data:

Note that the content-Type of the posted data is application/xml

<?php
  $filename = 'consoleexport.log';

  if (!$handle = fopen($filename, 'a'))
  {
    echo 'File "'.$filename.'" could not be opened';
    exit;
  }

  ob_start();
  $content = file_get_contents('php://input');
  $content .= "\n";
  ob_clean();

  if (!fwrite($handle, $content))
  {
    echo 'Can\'t write into file "'.$filename.'"';
    exit;
  }

  echo 'Done!';
  fclose($handle);
?>

Honza