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Home/ Questions/Q 8501773
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T01:18:04+00:00 2026-06-11T01:18:04+00:00

I have IPagedList interface which implements IList like this public interface IPagedList<T> : IList<T>

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I have IPagedList interface which implements IList like this

public interface IPagedList<T> : IList<T>
{
    int PageCount { get; }
    int TotalItemCount { get; }
    int PageIndex { get; }
    ...
}

Now I want to use this IPagedList to represent data with pagination.
I’m trying to convert existing code which was using IList to IPagedList

public IList<MyViewModel> Data
{
  get
  {         
    List<MyViewModel> myVal = new List<MyViewModel>();
    foreach (MyModel m in data)
    {
       myVal.Add(new MyViewModel(m));
    }
    return myVal;
  }
}

So, I’m wondering why this cannot be converted to

public IPagedList<MyViewModel> Data
{
   get
    .... 

cause IPagedList implements IList and how can I fix this.

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  1. Editorial Team
    Editorial Team
    2026-06-11T01:18:06+00:00Added an answer on June 11, 2026 at 1:18 am

    IPagedList<T> implements IList<T> and List<T> also implements IList<T>, that’s correct.

    But that doesn’t mean that a List<T> can be converted into an IPagedList<T>. That are still two different types. Think about it: A Porsche is a car, a Peugeot is a car, still they aren’t interchangable.

    You need to have a concrete implementation of the IPagedList<T> interface. If you have one, you can use this code:

    public IList<MyViewModel> Data 
    { 
        get 
        { 
            var myVal = new PagedList<MyViewModel>(); 
            foreach (MyModel m in data) 
            { 
                myVal.Add(new MyViewModel(m)); 
            } 
            return myVal; 
        } 
    } 
    
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