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Home/ Questions/Q 5982365
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T22:04:36+00:00 2026-05-22T22:04:36+00:00

I have javascript object defined like this: function SocialMiner() { var verbose=true; var profileArray=new

  • 0

I have javascript object defined like this:

function SocialMiner() 
{


var verbose=true;

var profileArray=new Array();

var tabUrl;

this.getTabUrl=function()
{
    logToConsole("getTabUrl is called");


    chrome.tabs.getSelected(null, function(tab)
    {
        tabUrl = tab.url;
        logToConsole(tabUrl);

    });

    return tabUrl;
}   `

Then I call this function on SocialMiner ojbect like this:

 var pageUrl=miner.getTabUrl();
 miner.logToConsole(pageUrl);

What is the reason that first call to logToConsole successfully prints the Url, while second one says undefined. Am I not returning the same value from the function ?

Update: This is how I have defined logToConsole:

function logToConsole(text) 
    {
        if (verbose)
            console.log(text);
    }

    this.logToConsole=logToConsole;
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  1. Editorial Team
    Editorial Team
    2026-05-22T22:04:37+00:00Added an answer on May 22, 2026 at 10:04 pm

    In the second example, you are calling logToConsole as if it is a function of the miner object, which is is not.

    miner.logToConsole
    

    Edit

    Per comments about github example, this should make the logToConsole function par of the SocialMiner object. However, I didn’t read the class thoroughly, so proceed with caution with regards to how it is intended to be used.

    this.logToConsole=function(text) 
    {
        if (verbose)
            console.log(text);
    }
    
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