Question

I have just started my HTTPREQUEST application and I am trying to set up my php files first.

I have this insert function on my wamp/www/MenuBook/ folder :

<?php

// array for JSON response
$response = array();

// check for required fields
if (isset($_POST['table_ID']) && isset($_POST['MenuBook']) && isset($_POST['order_status'])&& isset($_POST['order_date'])&& isset($_POST['order_receipt'])) {

    $tableID = $_POST['table_ID'];
    $menuBook = $_POST['MenuBook'];
    $order_status = $_POST['order_status'];
    $order_date = $_POST['order_date'];
    $order_receipt = $_POST['order_receipt'];

    // inlude db connect class
    require_once __DIR__ . '/DBConnect.php';

    // connecting to db
    $db = new DB_CONNECT();

    // mysql inserting a new row
    $result = mysql_query("INSERT INTO orderdb(table_ID,MenuBook,order_status,order_date,order_receipt) VALUES('$table_ID', '$menuBook', '$order_status','$order_date','$order_receipt')");

    // check if row inserted or not
    if ($result) {
        // successfully inserted into database
        $response["success"] = 1;
        $response["message"] = "Order successfully created.";

        // echoing JSON response
        echo json_encode($response);
    } else {
        // failed to insert row
        $response["success"] = 0;
        $response["message"] = "Oops! An error occurred.";

        // echoing JSON response
        echo json_encode($response);
    }
} else {
    // required field is missing
    $response["success"] = 0;
    $response["message"] = "Required field(s) is missing";

    // echoing JSON response
    echo json_encode($response);
}
?>

Now I would like to check if it would insert data into the database using my browser something like this :

localhost/MenuBook/insertOrder.php?$table_ID=003&$MenuBook=01&$order_status=PENDING&$order_date=2013-01-17&$order_receipt=NO

as of now it returns this in the browser:

{"success":0,"message":"Required field(s) is missing"}

Any ideas how I could try and check this?

Answer 1

This will not insert data because:

1. You are passing variables in URL (GET Method) and using them in your script using $_POST.
2. Also you have not even correctly passed the variables in URL it must be table_ID, MenuBook etc instead of $table_ID,$MenuBook.

The solution is either user $_GET or $_REQUEST in your script or if possible pass the values using POST method (an better choice).

For testing:
If you have used $_GET or $_REQUEST in your script, simply copy-paste the generated URL into the browser and have a test run.
Else if have used POST create a sample form(If you don’t have) and submit it to have a test.