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Home/ Questions/Q 7600941
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T23:02:33+00:00 2026-05-30T23:02:33+00:00

I have libx.so , and it exports a function and a global char *

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I have libx.so, and it exports a function and a global char *,

char *c_ptr = 0;

void foo(char *s)
{
    c_ptr = s;
}

In python, I pass a str to foo in 2 ways,

>>>libx = ctypes.CDLL("./libx.so")
#pass a raw str
>>>libx.foo("string")

#pass a c_char_p object
>>>libx.foo(c_char_p("strng"))

Q

1.I think, libx.foo("string") passes a Python str object to a C function which will later assign the string to char *c_ptr. I wonder, will c_ptr points to the str object "string" after the call foo? Cuz I presume the str object "string" will be garbage-collected after the call to foo, right?

2.Are the 2 ways (passing "string" and c_char_p("string")) difference in effect?
Are they different in effect?

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  1. Editorial Team
    Editorial Team
    2026-05-30T23:02:34+00:00Added an answer on May 30, 2026 at 11:02 pm

    1: What is Happening

    ctypes does adapt the Python string, correctly guessing that the function takes a char*. Effectively, libx.foo("string") is equivalent to the second example libx.foo(c_char_p("string")) with a little runtime adaptation.

    Your intuition about the string being garbage collected shortly after the call is correct. Nothing in Python retains a reference to the adapted c_char_p view of the string, and thus it will be returned to the object pool — likely to be re-issued in the future. Which means that the char* c_ptr will probably point at junk very soon.

    2: Different in Effect

    The second form allows you to keep a reference to the view passed to the C function. If you changed the example slightly:

    >>> s = c_char_p("string")
    >>> libx.foo(s)
    

    Then as long as a reference is maintained to s, the c_ptr value will be valid. You could accomplish that by just keeping a reference in the module implementing your binding to libx.

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