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Home/ Questions/Q 8923069
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T07:01:00+00:00 2026-06-15T07:01:00+00:00

I have list of lists: [[‘lorem’, [‘a’, ‘b’, ‘c’, ‘d’]], [‘ipsum’, [‘e’]], [‘dolor’, [‘f’,’g’]],

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I have list of lists:

[['lorem', ['a', 'b', 'c', 'd']], ['ipsum', ['e']], ['dolor', ['f','g']], ['sit', ['h', 'i']]]

how to achieve this one?

lorem (a + b + c + d); ipsum (e); dolor (e + g); sit (h + i)

So far, I’ve tried:

print '\n'.join('%s %s' % x for x in list) 

with no luck.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T07:01:03+00:00Added an answer on June 15, 2026 at 7:01 am
    In [14]: L = [['lorem', ['a', 'b', 'c', 'd']], ['ipsum', ['e']], ['dolor', ['f', 'g']], ['sit', ['h', 'i']]]
    
    In [15]: '; '.join("%s (%s)" %(elem[0], " + ".join(elem[1])) for elem in L)
    Out[15]: 'lorem (a + b + c + d); ipsum (e); dolor (f + g); sit (h + i)'
    

    OR

    In [18]: L = [(e[0], " + ".join(e[1])) for e in L]
    
    In [19]: L
    Out[19]: 
    [('lorem', 'a + b + c + d'),
     ('ipsum', 'e'),
     ('dolor', 'f + g'),
     ('sit', 'h + i')]
    
    In [20]: '; '.join("%s (%s)" %(e[0], e[1]) for e in L)
    Out[20]: 'lorem (a + b + c + d); ipsum (e); dolor (f + g); sit (h + i)'
    
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