Question

I have:

list_nums = [1,18]
list_chars = ['a','d']

I want:

list_num_chars = [{'num':1, 'char':'a'},
                  {'num':18, 'char':'d'}]

Is there a more elegant solution than:

list_num_chars = [{'num':a, 'char':b} for a,b in zip(list_nums, list_chars)]

Answer 1

If the initial lists are very long, you might want to use itertools.izip() instead of zip() for slightly improved performance and less memory usage, but apart from this I can’t think of a significantly “better” way to do it.