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Home/ Questions/Q 6623045
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T21:29:10+00:00 2026-05-25T21:29:10+00:00

I have little experience in GUI programming but I’m writing a GUI application with

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I have little experience in GUI programming but I’m writing a GUI application with PyQt. With this application, user can open a binary file and do some editing with it.

When the file is opened, I do some processing that takes a while (~15s). So when the user pick the file and press the “Open” button in the file open dialog, the GUI is frozen. What’s the best way to achieve a better user experience?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-25T21:29:10+00:00Added an answer on May 25, 2026 at 9:29 pm

    Load in the background showing the progress via a Gauge in the statusbar.

    To to this, you can initiate the loading using QThread. Your thread class can look as follows (assuming parent will have an attribute progress):

    QtFileLoader(QtCore.QThread):
        def __init__(self,parent=None, filepath=None):
            QtCore.QThread.__init__(self,parent)
            self.data = None
            self.filepath = filepath
    
        def run(self):
            """ load data in parts and update the progess par """
            chunksize = 1000
            filesize = ... # TODO: get length of file
            n_parts = int(filesize/chunksize) + 1
            with open(self.filepath, 'rb') as f:
                for i in range(n_parts):
                    self.data += f.read(chunksize)
                    self.parent.progress = i 
    

    The question whether to use QThread or trheading.Thread is discussed here

    edit (according to hint of @Nathan):
    On the parent, a timerfunction should check, say each 100ms, the value of self.parent.progress and set the progressbar accordingly. This way, the progressbar is set from within the main thread of the GUI.

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