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Home/ Questions/Q 7936971
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T22:23:03+00:00 2026-06-03T22:23:03+00:00

I have looked into the documentation for dynamic objects but i wasn’t able to

  • 0

I have looked into the documentation for dynamic objects but i wasn’t able to find a solution
to my current problem.

I have this code :

dynamic sampleObject = new ExpandoObject();

string columnName = checkBox.Content.ToString();

sampleObject.columName = myObservableCollection;

Now, the name of my added property will be columnName, but I would like it to be the content of my checkbox.

How should I implement that ?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T22:23:04+00:00Added an answer on June 3, 2026 at 10:23 pm

    Use a dictionary of named values instead of dynamic properties.

    You can use a Dictionary converter to bind to specific entries in the dictionary (using the converter parameter value as the key). Code below from this link

    public class DictionaryItemConverter : IValueConverter
    {
        public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
        {
            var dict = value as Dictionary<string, string>;
            if (dict != null)
            {
                return dict[parameter as string];
            }
            throw new NotImplementedException();
        }
    
        public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
        {
            throw new NotImplementedException();
        }
    }
    

    Where you add columns to the grid via code you will need to create a binding with the correct converter and name converter parameter.

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