Question

I have made a program which takes a 1000 digit number as input.
It is fixed, so I put this input into the code file itself.
I would obviously be storing it as Integer type, but how do I do it?

I have tried the program by having 1000 digits in the same line. I know this is the worst possible code format! But it works.

How can assign the variable this number, and split its lines. I read somewhere something about eos? Ruby, end of what?

I was thinking that something similar to comments could be used here.

Help will be appreciated.

the basic idea is to make this work:

a=3847981438917489137897491412341234
983745893289572395725258923745897232

instead of something like this:

a=3847981438917489137897491412341234983745893289572395725258923745897232

Answer 1

Haskell doesn’t have a way to split (non-String) literals across multiple lines. Since Strings are an exception, we can shoehorn in other literals by parsing a multiline String:

v = read
    "32456\
    \23857\
    \23545" :: Integer

Alternately, you can use list syntax if you think it’s prettier:

v = read . concat $
    ["32456"
    ,"24357"
    ,"23476"
    ] :: Integer

The price you pay for this is that some work will be done (once) at runtime, namely, the parsing (e.g. read).