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Home/ Questions/Q 6750813
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T12:51:10+00:00 2026-05-26T12:51:10+00:00

I have main dictionary. mainDict = {‘count’: 10, ‘a’: {‘abc’: {‘additional’: 0, ‘missing’: 0,

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I have main dictionary.

mainDict = {'count': 10, 'a': {'abc': {'additional': 0, 'missing': 0, 'changed': 0}}}

Now i have new dictionary with same keys as in mainDict, called this dictionary as b with different values.

b = {'count': 20, 'a': {'abc': {'additional': 10, 'missing': 10, 'changed': 10}}}

I want to update(addition operation) the values of keys in main dictionary so i do..

mainDict = {'count': mainDict['count'] + b['count'], 'a': }

I am stuck at updating values of key a. If i use mainDict.update(b) then it will replace previous values. Any efficient solution??

The final output required is:

mainDict = {'count': 30, 'a': {'abc': {'additional': 10, 'missing': 10, 'changed': 10}}}

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T12:51:11+00:00Added an answer on May 26, 2026 at 12:51 pm
    def recursive_dict_sum_helper(v1, v2):
        # "add" two values: if they can be added with '+', then do so,
        # otherwise expect dictionaries and treat them appropriately.
        try: return v1 + v2
        except: return recursive_dict_sum(v1, v2)
    
    def recursive_dict_sum(d1, d2):
        # Recursively produce the new key-value pair for each
        # original key-value pair, and make a dict with the results.
        return dict(
            (k, recursive_dict_sum_helper(v, d2[k]))
            for (k, v) in d1.items()
        )
    
    mainDict = recursive_dict_sum(mainDict, b)
    
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