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Home/ Questions/Q 8439113
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T07:55:05+00:00 2026-06-10T07:55:05+00:00

I have many objects using few classes (means elements visual categorization like in html+css).

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I have many objects using few classes (means elements visual categorization like in html+css). Classes are not known at compile-time and they are used in conditions many times.

To improve performance I’ve got one solution:

public class ElementClass {

    private static final Map<String, ElementClass> classes = new HashMap<>();

    public final String name;
    public final String lowerName;

    public ElementClass(String name, String lowerName) {
        this.name = name;
        this.lowerName = lowerName;
    }

    public static ElementClass get(String name) {
        String lower = name.toLowerCase();
        ElementClass c = classes.get(lower);
        if (c == null) {
            c = new ElementClass(name, lower);
            classes.put(lower, c);
        }
        return c;
    }
}

The method get is used very less than comparison of ElementClass variables. It is in parsing configurations and for some static variables. I’m not sure if this is the best way to go, because I’m Java beginner.

The examples usage of ElementClass:

// contains element styles based on it's class
Map<ElementClass,ElementStyle> styles;

void exampleFunction() {
    ElementClass c = ElementClass.get("special");
    for( Element e : elements ) {
        if( e.cls == c ) doSomethingSpecial();
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T07:55:06+00:00Added an answer on June 10, 2026 at 7:55 am

    This would be a textbook implementation of a cache. If there aren’t many ElementClasses and if your program is single-threaded, this will be enough.

    I don’t see the need to keep the lowercase name inside the ElementClass. It is enough to use it as the map key. I also assume there’s more to the ElementClass in your project since now it just contains a name.

    Update

    After clarification it became obvious that you do indeed only intend to use the String name. In such a case it would be much better to make each Element just contain its lowercase name, but interned:

    public Element(String name) {
      this.name = name.toLowerCase().intern();
    }
    

    Then you can compare element.name == "special" and be guaranteed to match any names that are equal to "special".

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