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Home/ Questions/Q 9186233
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T19:28:29+00:00 2026-06-17T19:28:29+00:00

I have many to many association between words and definitions . words: +—————–+————–+——+—–+———+—————-+ |

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I have many to many association between words and definitions.

words:
+-----------------+--------------+------+-----+---------+----------------+
| Field           | Type         | Null | Key | Default | Extra          |
+-----------------+--------------+------+-----+---------+----------------+
| id              | int(11)      | NO   | PRI | NULL    | auto_increment |
+-----------------+--------------+------+-----+---------+----------------+

definitions:
+-------------------+--------------+------+-----+---------+----------------+
| Field             | Type         | Null | Key | Default | Extra          |
+-------------------+--------------+------+-----+---------+----------------+
| id                | int(11)      | NO   | PRI | NULL    | auto_increment |
| language_id       | int(11)      | YES  | MUL | NULL    |                |
+-------------------+--------------+------+-----+---------+----------------+

definitions_words:
+---------------+---------+------+-----+---------+-------+
| Field         | Type    | Null | Key | Default | Extra |
+---------------+---------+------+-----+---------+-------+
| definition_id | int(11) | NO   | PRI | NULL    |       |
| word_id       | int(11) | NO   | PRI | NULL    |       |
+---------------+---------+------+-----+---------+-------+

I would like to get all word records which have exactly one definition with language_id = 1.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T19:28:30+00:00Added an answer on June 17, 2026 at 7:28 pm
    SELECT  a.ID, COUNT(*) totalRecordCount
    FROM    words a
            INNER JOIN definition_words b
                ON a.ID = b.word_ID
            INNER JOIN definitions c
                ON b.definition_id = c.ID
            INNER JOIN
            (
                SELECT  id,
                        SUM(language = 1) totalCount
                FROM    definitions
                GROUP   BY id
            ) d ON c.ID = d.ID AND 
                   d.TotalCount = 1
    GROUP   BY a.ID
    
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