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Home/ Questions/Q 7748883
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T10:53:58+00:00 2026-06-01T10:53:58+00:00

I have merged multiple jpeg files into one single .bin file. ….. ……… while(true){

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I have merged multiple jpeg files into one single .bin file.

.....
.........
while(true){
             if (q.numOfFiles() > 0) {
              source = q.getNextFile();
              in = new DataInputStream(new BufferedInputStream(new FileInputStream(source)));
               byte[] buf = new byte[1024];
               int len;
               while ((len = in.read(buf)) > 0) {
                out.write(buf, 0, len);
               }
               String s = "filename=="+source.getName()+"==filename";
               out.write(s.getBytes());
               out.flush();
               System.out.println("merged--"+source.getName());
             }
                }
........
........

as you can see i am appending “filename==”+source.getName()+”==filename” after end of each file.
Now i want to separate all those jpegs with their actual file names.
How can i read the separators that I’ve inserted in the merged files ?

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  1. Editorial Team
    Editorial Team
    2026-06-01T10:54:00+00:00Added an answer on June 1, 2026 at 10:54 am

    As above in the comments:
    Sugestion/answer to adapt your point of view:

    Using a single file zip to ship multiple files.

    How to create zip in Java

    And to extract:

    Extract from zip in Java

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