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Home/ Questions/Q 8923881
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T07:15:05+00:00 2026-06-15T07:15:05+00:00

I have module foo, inside this module I dynamically created class: def superClassCreator(): return

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I have module foo, inside this module I dynamically created class:

def superClassCreator():
    return type("Bar", (object,), {})

Now, what I want to achieve is to make this new dynamic class visible as a class of this module:

import foo
dir(foo)
>>> [... 'Bar' ...]

Do you know how to do this?

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  1. Editorial Team
    Editorial Team
    2026-06-15T07:15:06+00:00Added an answer on June 15, 2026 at 7:15 am

    You can use Bar = superClassCreator() in foo (at the module level).

    Alternatively, from another module, you can add Bar as an attribute on foo:

    import foo
    
    foo.Bar = superClassCreator()
    

    or, if the name must be taken from the generated class:

    import foo
    
    generatedClass = superClassCreator()
    setattr(foo, generatedClass.__name__, generatedClass)
    

    From within the foo module, you can set it directly on globals():

    generatedClass = superClassCreator()
    globals()[generatedClass.__name__] = generatedClass
    del generatedClass
    

    with an optional del statement to remove the generatedClass name from the namespace again.

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