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Home/ Questions/Q 8164277
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T19:16:56+00:00 2026-06-06T19:16:56+00:00

I have my class, where I overloaded the ! operator: class obj { public:

  • 0

I have my class, where I overloaded the ! operator:

class obj
{
public:

    bool operator!() const
    { return this->str.length() == 0; }

private:

    string str;

};

With the ! operator i want to check the obj validity, so:

obj o;

// if o is not a valid object
if(!o)
   cerr << "Error";

Now I want to have the possibility to do this:

// if o is a valid object
if(o)
   cout << "OK";

How can I do?

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  1. Editorial Team
    Editorial Team
    2026-06-06T19:16:57+00:00Added an answer on June 6, 2026 at 7:16 pm

    Using C++11, you can do this by having an explicit operator bool:

    explicit operator bool() const {
        return !!*this;
    }
    

    This operator is called if you ever need to cast your object to a bool explicitly (which is done by the if statement automatically). The implementation works by calling your operator ! on the receiver object, then returning the opposite result.

    Hope this helps!

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