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Home/ Questions/Q 6982307
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:16:14+00:00 2026-05-27T18:16:14+00:00

I have my own mathematical Vector class that I use in my code. I

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I have my own mathematical Vector class that I use in my code. I have a new need to generalize my vector class to n dimensions instead of just two.

My question is, what’s the best way to implement the operator overloads, and is there a significant overhead to doing this?

I now store the values in an array

double *vals;
....
vals = new double[dimension];

With this, I implement the + operator like so:

Vector Vector::operator+(Vector v) 
{
    Vector ret = Vector(dimension);
    for (int i = 0; i < dimension; i ++)
    {
        ret.vals[i] = vals[i] + v.vals[i];
    }
}

This operation will be done a LOT and has to run fast. Is this significantly worse than the old version (as far as speed)?

Vector Vector::operator+(Vector v) {
    return Vector(x + v.x, y + v.y);
}

Thanks for any input!

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:16:15+00:00Added an answer on May 27, 2026 at 6:16 pm

    If you want a fast vector class then use templates for the size:

    template<std::size_t size>
    class Vector {
      double data[size];
    public:
      double& operator[](std::size_t x) { return data[x]; }
    };
    
    template<std::size_t size>
    Vector<size> operator+(Vector<size> lhs, const Vector<size>& rhs) {
      for (std::size_t i = 0; i < size; ++i)
        lhs[i] += rhs[i];
      return lhs;
    }
    

    Having them be dynamic size is only unnecessary if you want to re-size them, or if they are incredibly large.

    There are ways to get much faster than this, such as SSE. You should use a dedicated math library if you want something highly optimized.

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