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Home/ Questions/Q 301073
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T06:58:20+00:00 2026-05-12T06:58:20+00:00

I have my templated container class that looks like this: template< class KeyType, class

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I have my templated container class that looks like this:

template<
   class KeyType, 
   class ValueType, 
   class KeyCompareFunctor   = AnObnoxiouslyLongSequenceOfCharacters<KeyType>, 
   class ValueCompareFunctor = AnObnoxiouslyLongSequenceOfCharacters<ValueType> 
>
   class MyClass
   {
      [...]
   }

Which means that when I instantiate an object of this class, I can do it several different ways:

MyClass<MyKeyType, MyValueType> myObject;
MyClass<MyKeyType, MyValueType, MyCustomKeyCompareFunctor> myObject;
MyClass<MyKeyType, MyValueType, MyCustomKeyCompareFunctor, MyCustomValueCompareFunctor> myObject;

Those are all good. The problem comes when I want to instantiate a MyClass that uses a non-default version of the ValueCompareFunctor argument, but I still want to use the default value of the KeyCompareFunctor argument. Then I have to write this:

MyClass<MyKeyType, MyValueType, AnObnoxiouslyLongSequenceOfCharacters<MyKeyType>, MyCustomValueCompareFunctor> myObject;

It would be much more convenient if I could somehow omit the third argument and just write this:

MyClass<KeyType, ValueType, MyCustomValueCompareFunctor> myObject;

Since the MyCustomValueCompareFunctor works only on objects of type MyValueType and not on objects of type MyKeyType, it seems like the compiler could at least theoretically work out what I meant here.

Is there a way to do this in C++?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T06:58:20+00:00Added an answer on May 12, 2026 at 6:58 am

    In general, both in templates and functions or methods, C++ lets you use default for (and thereby omit) only trailing parameters — no way out.

    I recommend a template or macro to shorten AnObnoxiouslyLongSequenceOfCharacters<MyKeyType> to Foo<MyKeyType> — not perfect, but better than nothing.

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