Question

I have mysql query and I need order by timeaccept

    SELECT id, name, level as lvl, leader as par3
FROM Road
WHERE Road.id LIKE '180' 
UNION ALL SELECT id, name, lvl, lastonline, dnd, null, raceid, currenthp, dressed_hp as hp 
FROM Users 
WHERE rid LIKE '180' AND id NOT LIKE (SELECT leader FROM Road WHERE id LIKE '180')
UNION ALL 
SELECT Users.id as id, Users.name, lvl, lastonline, dnd, currentlocid, Location.name as locname, currenthp, dressed_hp as hp 
FROM Users LEFT JOIN Location ON (Location.id = currentlocid) 
WHERE Users.id LIKE(SELECT leader FROM Road WHERE id LIKE '180') ORDER BY Users.timeacceptinvite

Answer 1

select x.* from (
  SELECT
    id, name, level as lvl, leader as par3, timeacceptinvite
  FROM Road
  WHERE Road.id LIKE '180' 
  UNION ALL
  SELECT
    id, name, lvl, lastonline, dnd, null, raceid, currenthp, dressed_hp as hp, timeacceptinvite 
  FROM Users 
  WHERE rid LIKE '180'
    AND id NOT LIKE (SELECT leader FROM Road WHERE id LIKE '180')
  UNION ALL 
  SELECT
   Users.id as id, Users.name, lvl, lastonline, dnd, currentlocid, Location.name as locname, currenthp, dressed_hp as hp, timeacceptinvite 
  FROM Users LEFT JOIN Location ON (Location.id = currentlocid) 
  WHERE Users.id LIKE(SELECT leader FROM Road WHERE id LIKE '180')
) as x
 ORDER BY x.timeacceptinvite

edit 1

but i think that you will receive different number of columns error…